How to make `return` return a var and text

Question

I have this code:

#include <iostream> #include <string> using namespace std; class Event{ public: Event(int x, int y, string z){ setEvent(x, y, z); }//Constructor void setEvent(int a, int b, string c){ if(a >= 0){ if(a < b){ if(b <= 24){ start_time = a; end_time = b; event_name = c; } else cout <<"The end time for the event needs to be <=24 hours"; } else cout <<"The start time for the event needs to be smaller than the end time"; } else cout <<"The start time for the event needs to be >=0 hours"; }//Code to set an event and check if the event is valid within the precondition void rename(string r){//Code to rename event event_name = r; } string duration(){ int time_length = end_time - start_time; if(time_length == 1) return "1 hour";//I am stuck over here!!! else return time_length "hour"; } private: int start_time; int end_time; string event_name; };

If you look void duration() in the public class, I am trying to make return return text in one part and a var and text in another part. But I am unable to make it work.

 main.cpp:30:16: error: could not convert 'time_length' from 'int' to 'std::__cxx11::string {aka std::__cxx11::basic_string<char>}' else return time_length "hour"; ^~~~~~~~~~~

main.cpp:30:28: error: expected ';' before string constant else return time_length "hour"; ^~~~~~

Is there a way to make return work or any alternative to fix this problem/code.

1st of all you can't return anything from a void function. 2nd return something like a std::pair<int, std::string> for example. — user0042
– user0042, Commented Dec 19, 2017 at 0:49
Instead of giving it a downvote, please give feedback as well — Manav Dubey
– Manav Dubey, Commented Dec 19, 2017 at 0:50
@user0042 can you explain the 2nd you meant, it is unclear to what you mean. — Manav Dubey
– Manav Dubey, Commented Dec 19, 2017 at 0:51
@user0042 i know that is wrong to ask stuff, but why doesn't return text? — Manav Dubey
– Manav Dubey, Commented Dec 19, 2017 at 0:53
You might be looking for return std::to_string(time_length) + " hour"; — Praetorian
– Praetorian, Commented Dec 19, 2017 at 0:54

Ryan Turnbull · Accepted Answer · 2017-12-19 00:52:26Z

Using void means the function will return nothing, so you cannot actually retreive any variables from this function.

A fix would be to give the function type std::string, EG

string duration(){ int time_length = end_time - start_time; if(time_length == 1) return "1 hour";//I am stuck over here!!! else //Formulate a string otherwise }

Note you are going to have to look into building a string with C++, and put that logic into your else statement.

If you wish to return a pair, you are going to have to write another function with return type std::pair<int, std::string>

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