Running bash script with python [duplicate]

Question

I wrote python script to run bash script it runs it with this line:

result = subprocess.Popen(['./test.sh %s %s %s' %(input_file, output_file, master_name)], shell = True) if result != 0: print("Sh*t hits the fan at some point") return else: print("Moving further")

Now I having troubles when bash script fails, python doesn't continue doing what it was doing it just ends. How can I make it so that python script would continue running after bash fails?

Have you tried try/except

Benoît P
– Benoît P

2019-01-31 10:48:30 +00:00
Commented Jan 31, 2019 at 10:48 — Benoît P
– Benoît P, Commented Jan 31, 2019 at 10:48

Colonder · Accepted Answer · 2019-01-31 10:54:18Z

1

You forgot about the communicate. Besides you return when the bash script fails so no wonder the python "just stops".

from subprocess import Popen, PIPE p = Popen(..., stdout=PIPE, stderr=PIPE) output, error = p.communicate() if p.returncode != 0: print("Sh*t hits the fan at some point %d %s %s" % (p.returncode, output, error)) print("Movign further")

edited Jan 31, 2019 at 10:54

answered Jan 31, 2019 at 10:49

Colonder

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3 Comments

LeTadas Over a year ago

and what it does?

Colonder Over a year ago

Gets the error's stacktrace. But I realized that you just return when the returncode != 0... No wonder that it "just ends"

tripleee Over a year ago

As the documentation already tells you, don´t use bare Popen if you can use one of the higher-level functions which take care of exactly these details for you. In this case, check_call or run(..., check=True) will raise an exception if the subprocess fails.

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