I am trying to search an Array for a value, if that value is found then return that the value is found and the index at which it was found. If the value is not found then the index returned is -1
array = [1, 2, 3] search_value = gets.chomp array.map.include?(search_value) || -1 if index != -1 puts "Found " + search_value + " at " + index.to_s The expected result is Found 2 at 1 instead I receive Found 2 at True, I understand why this is happening but I don't know how to fix it
You simply can use array.index(element)
Example:
array = [1, 2, 3, 4, 5] array.index(5) || -1 # returns 4 (because 5 is at 4th index) array.index(6) || -1 # returns -1 You're looking for Array#index, which returns nil in case the value is not part of the array.
To return -1 when the value is not found:
index = array.index(search_value) || -1 
map? IMO it is useless in this case and actually makes every think slower.
include? to index. Updating it...array = ["1", "2", "3"] search_value = gets.chomp index = array.index(search_value) || -1 puts "Found " + search_value + " at " + index.to_s // Type 2 // Expected output: Found 2 at 1 I don't know why array = [1, 2, 3] doesn't work correctly but I try array = ["1", "2", "3"] instead it works. Hope someone can explain a little bit.
search_value into Integer with to_i, so you can have them as int the array too.