Is there a programmatic way to distinguish whether bash script was executed by user and via shell_exec in PHP?

I've written simple DB backup script that does the job with no issues whatsoever, but to avoid embedding any credentials, I pass everything as arguments.

private function dumpDatabase(): void { $this->fileSystem->disk('local')->makeDirectory('temp'); $relativePathToDump = 'storage/app/temp/dump.sql'; $executableChunks = [ 'HOST=' . config('database.connections.mysql.host'), 'PORT=' . config('database.connections.mysql.port'), 'USER=' . config('database.connections.mysql.username'), 'PASSWORD=' . config('database.connections.mysql.password'), 'DATABASE_NAME=' . config('database.connections.mysql.database'), 'RELATIVE_PATH_TO_DUMP=' . $relativePathToDump, base_path('bin/backup_database.sh'), ]; $command = implode(' ', $executableChunks); shell_exec($command); } 

The script itself:

#!/usr/bin/env bash mysqldump --force --routines -h $HOST --port=$PORT -u $USER -p$PASSWORD $DATABASE_NAME > $RELATIVE_PATH_TO_DUMP 

Is there a way to immediately stop the script's execution if it was triggered by user manually via:

./bin/backup_database.sh 

but let it do the job when called via:

shell_exec($command);

I could add more checks to see if arguments are present:

if [[ -z "${HOST}" ]]; then echo "Database host (HOST=) has not been provided." exit 1 fi 

but this is not about arguments but about who / what is the "executee" of the script. Is it doable?

if [[ not triggered programatically by shell_exec ]]; then echo "Bye" exit 1 fi