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I am trying to assign values to a struct array. However, I'm getting the "Expected expression" error. Is there something that I'm missing? I'm using Xcode in case that matters.

#include <stdio.h> #include <stdlib.h> struct MEASUREMENT { float relativeHumidity; float temperature; char timestamp[20]; }; int main() { struct MEASUREMENT measurements[5]; measurements[0] = {0.85, 23.5, "23.07.2019 08:00"}; //Expected expression error measurements[1] = {0.71, 19.0, "04.08.2019 10:21"}; //Expected expression error measurements[2] = {0.43, 10.2, "07.08.2019 02.00"}; //Expected expression error measurements[3] = {0.51, 14.3, "20.08.2019 14:45"}; //Expected expression error measurements[4] = {0.62, 10.9, "01.09.2019 01:00"}; //Expected expression error

Thanks!

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Listing values in braces is a special syntax for initializations in declarations. A list in braces does not by itself form an expression that can be used in assignments.

You can provide initial values in this form when defining the array:

struct MEASUREMENT measurements[5] = { {0.85, 23.5, "23.07.2019 08:00"}, {0.71, 19.0, "04.08.2019 10:21"}, {0.43, 10.2, "07.08.2019 02.00"}, {0.51, 14.3, "20.08.2019 14:45"}, {0.62, 10.9, "01.09.2019 01:00"}, };

In expressions, you can define a temporary object using a compound literal and then assign its value to another object. A compound literal is formed with a type in parentheses followed by a brace-enclosed list of initializers:

measurements[0] = (struct MEASUREMENT) {0.85, 23.5, "23.07.2019 08:00"}; measurements[1] = (struct MEASUREMENT) {0.71, 19.0, "04.08.2019 10:21"}; measurements[2] = (struct MEASUREMENT) {0.43, 10.2, "07.08.2019 02.00"}; measurements[3] = (struct MEASUREMENT) {0.51, 14.3, "20.08.2019 14:45"}; measurements[4] = (struct MEASUREMENT) {0.62, 10.9, "01.09.2019 01:00"};
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