How to sort javascript objects based on their properties, specifying the property

Question

There are lots of answers on SO for similar questions, which all describe how to implement a custom sort function to sort an array of javascript objects.

However, I was wondering if it might be possible to implement a more abstract custom sort that would allow me to pass the name of the property of the objects on which I want it to sort. This might save me having to implement very similar functions over and over again.

So if I had an object constructor like:

function Car(mph, cc) { this.maxSpeed = mph; this.engineSize = cc; }

then instead of implementing two sort functions:

function sortCarsOnMaxSpeed(a, b) { return a.maxSpeed - b.maxSpeed; } function sortCarsOnEngineSize(a, b) { return a.engineSize - b.engineSize; }

I could have some sort of generic function such as:

function sortObjectsOnProperty(a, b, property) { return a[property] - b[property]; }

but the custom sort seems to only take 2 arguments.

Any suggestions as to how I could do this?

Many thanks.

SLaks · Accepted Answer · 2011-09-18 16:24:53Z

8

You need to write a function that takes a property name and returns a comparator:

function createComparator(property) { return function(a, b) { return a[property] - b[property]; }; }

You would use it like this:

arr.sort(createComparator("maxSpeed"));

answered Sep 18, 2011 at 16:24

SLaks

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1 Comment

partizanos Over a year ago

function createComparator(property) { return function(a, b) { if (a[property] > b[property]) return 1 if (a[property] < b[property]) return -1 return 0 }; } This works for string comparison to

krishwader · Accepted Answer · 2016-05-19 18:44:37Z

sort takes a function, which can be anonymous:

sort(array, function(a, b) { return a.maxSpeed - b.maxSpeed; });

If you really don't want this, you can define a sortObjectsOnProperty() function that return a sort callback like this:

function sortObjectsOnProperty(name) { return function(a, b) { return a[name] - b[name]; } }

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