I have the following sequence definition:
I can't find a way to write this in Latex. Any hints where to start?
2 Answers
Since the other cases questions ask some specific questions about it, here's a working example:
\documentclass{article} \usepackage{amsmath} \begin{document} \[ g(n) = \begin{cases} \frac{2}{3}n & \text{wenn } n \equiv 0 \mod 3,\\ \frac{4}{3}n + \frac{1}{3} & \text{wenn } n \equiv 1 \mod 3,\\ \frac{4}{3}n - \frac{1}{3} & \text{wenn } n \equiv 2 \mod 3. \end{cases} \] \end{document} The mathmode documentation is extremely helpful for answering these sorts of questions. You can find it on your system using texdoc or its equivalent.
\documentclass{article} \usepackage{amsmath} \begin{document} \begin{equation*} g(n) = \begin{cases} \frac{2}{3} n &\ text{wenn } n \equiv 0 \mod 3 \\ \frac{4}{3} n - \frac{1}{3} & \text{ wenn } n \equiv 1 \mod 3 \\ \frac{4}{3} n + \frac{1}{3} & \text{ wenn } n \equiv 2 \mod 3 \end{cases} \end{equation*} \begin{equation*} \def\arraystretch{1.3}% g(n) = \left\{\begin{array}{llll} \frac{2}{3} n & \text{wenn} & n \equiv 0 & \mod 3 \\ \frac{4}{3} n - \frac{1}{3} & \text{wenn} & n \equiv 1 & \mod 3 \\ \frac{4}{3} n + \frac{1}{3} & \text{wenn} & n \equiv 2 & \mod 3 \end{array}\right. \end{equation*} \end{document} 
casesenvironment. searchcasesfirst.