You can do a few things.
head and tail are both spec'd to display the first/last ten lines of a file by default - but if called w/ multiple arguments will do that for all and display the filenames for each. And, of course, for each, you can use the -n[num] argument to specify a number of lines other than the default ten that you would like to display. I assume your CTRL-C problem was related to the -f option - which would instruct tail to follow a file - you probably should just leave that out.
Another thing you might do - which will result in output a little different than in the question, but which you might still like, is...
grep -F '' ./*files
grep is also spec'd to display the filename for its matches when it is given multiple filename arguments - but grep does it at the head of every line. Like
seq 10 >nums.txt; grep -F '' /dev/null nums.txt
...which prints...
nums.txt:1 nums.txt:2 nums.txt:3 nums.txt:4 nums.txt:5 nums.txt:6 nums.txt:7 nums.txt:8 nums.txt:9 nums.txt:10
...and highlighted on my terminal. The /dev/null thing is just a little trick to force the multiple file arg behavior even when working with only a single file, and grep -F '' matches every line - even blank ones.
And here's head /dev/null nums.txt:
==> /dev/null <== ==> nums.txt <== 1 2 3 4 5 6 7 8 9 10
tail's output is identical in this case - but, again, both utilities only print so many lines of a file.
With the latest version of GNU sed you can use the F command like:
sed -s 1F ./*files
...or if you wanted a little border around the filename...
sed -se '1!b;i\\n---' -e 'F;i\---\n' nums.txt
...which does like...
--- nums.txt --- 1 2 3 4 5 6 7 8 9 10
Or if you wanted to get adventurous you could do...
tar -c ./*files | tr -s \\0 | cut -d '' -f1,2,13 | tr '\0' '\n'
...but that's probably not practical.
tailwithout-f. It will display the last 10 lines in each file and the filenames.