Is there a simpler way to do this? grep -v foo file | grep -v bar
There're probably very elegant ways to do it with egrep, but how to go with plain old grep?
EDIT: grep -v 'foo\|bar' file seems to work only with GNU grep. I'm on Solaris. Any solution for that?
You can have multiple tests in a single grep command by passing each expression with a -e argument instead of as the first non-option argument as you normally see:
$ grep -v -e foo -e bar file That says the same thing your command does: print lines from file that contain neither "foo" nor "bar".
Keep in mind that removing -v completely inverts this; it changes the logical operation, too! You get all lines that contain "foo" or "bar".
grep -Ev 'word1|word2' should work just fine
egrep -v 'word1|word2 \| is a GNU grep extension, but you can achieve the same thing in a portable way with -E and the | operator. You could also use curly braces for parameter expansion:
grep -v -e{foo,bar} which effectively is the same as:
grep -v -e foo -e bar (I don't have enough reputation points to add this as a comment)
On Solaris 11.4, if you set your PATH variable correctly to pick up the command line tools that are slightly more usable than the default set, then you would be able to use
grep -E -v 'foo|bar' file You get this more capable grep as your default grep if you set your PATH like so:
PATH=$(/usr/xpg6/bin/getconf PATH):$PATH This would add the following paths to the front of your existing PATH variable's value, on a default Solaris 11.4 system:
/usr/xpg6/bin:/usr/xpg4/bin:/usr/bin:/opt/developerstudio12.5/bin:/opt/solarisstudio12.4/bin See also man standards on a Solaris system.
-vflag is a negation.not(A or B) == not(A) and not(B)