Passing JSON to PHP

You don't need to call JSON.stringify(), when sending ajax-request, because $.ajax() function expects associative array of parameters, not string.

function callRemoteService(requestId, sObjectId, bObjectId) { $.ajax({ url: "../../../serviceRemoteEngine.php", dataType: "json", contentType: "application/json", type: "POST", timeout: 1000, data: {"requestId":requestId,"SOobjectId":sObjectId,"SBobjectId":bObjectId}, success: function(remoteResponse){ alert(remoteResponse.msg); } }); } 

PHP expects a post/get request to have key=value pairs. You're sending over a bare string, so it's just value. Since there's no key, PHP cannot (and will not) put anything into $_POST, since there's no key to attach the value to.

Try

data: {foo: JSON.stringify(...)} 

and

echo $_POST['foo'] 

instead.

Your PHP for the JSON is this:

echo json_encode(array("msg" => "message")); 

But you should see if adding proper JSON headers will help clear things up. Like this:

$json_data = json_encode(array("msg" => "message")); header('X-JSON: (' . $json_data . ')'); header('Content-type: application/x-json'); echo $json_data; 

Also, reading over your question again, you seem to be wanting to get the $_POST["SOobjectId"] immediately & then sent that back via JSON? Are you sure that $_POST contains anything? In your PHP file before you do anything else, do this:

echo '<pre>'; print_r($_POST); echo '</pre>'; 

Or do this for the $_REQUEST to see if data is transmitted:

echo '<pre>'; print_r($_REQUEST); echo '</pre>'; 

Perhaps you need to do this in your PHP file. Get the raw $_POST data via file_get_contents('php://input') and then decode it and handle it that way. All of my reworking—including this idea—below:

$json_decoded_array = json_decode(file_get_contents('php://input'), true); $json_data = json_encode(array("msg" => $json_decoded_array['SOobjectId'])); header('X-JSON: (' . $json_data . ')'); header('Content-type: application/x-json'); echo $json_data;