Im trying to pass a method as a parameter to method_2, execute this one and return the result:
def method_2( method_p, param ) res = method(method_p).call(param) return res end def method_1 klass = MyKlass.instance return method_2( klass.foo, "test" ) end this's MyKlass file:
class MyKlass def foo(param) param+param end end All I got is an error
wrong number of arguments (0 for 1) You can use symbols to refer to methods:
def method_2(method_symbol, *args) send method_symbol, *args end However, since you're calling the method on a specific object, you would either have to pass that in as an additional argument, or use a proc or a lambda, which is like a block wrapped in an object:
def method_2(proc, *args) proc.call(*args) end method_2(->(param){ klass.foo(param) }, "test") It's more common to just use blocks to do this:
def method_2(receiver, *args, &block) yield receiver, *args end method_2(klass, "test") do |receiver, param| receiver.foo(param) end All of these are fairly contrived examples; is there a specific problem you're trying to solve?
When you:
return method_2( klass.foo, "test" ) klass.foo requires one arg, that might be what's causing your error.
