How to store a compiled script name and execute it?(GCC)

Question

I am trying to make a shortcut code with gcc. The purpose is to compile and then automatically execute the compiled file.The code I am using looks like this,

gcc [email protected] -o $@ ./$@

But it won't execute as purposed. It is saying something like Segmentation Fault. How should I fix this?

Why are you using $@ instead of $1? The way you've written the script, it won't work with multiple arguments. — Barmar
– Barmar, Commented Mar 16, 2017 at 21:14
@Barmar $@ could make sense in the context of a Makefile. Still, not enough information given here to figure out what's going on... — ephemient
– ephemient, Commented Mar 17, 2017 at 6:40

yugr · Accepted Answer · 2017-03-17 17:21:02Z

1

You probly want

#!/bin/sh -e if ! test $# -gt 0 -a -f "$1"; then echo >&2 "Usage: $(basename $0) FILE [ARG]..." exit 1 fi F="$1" shift X=$(echo "$F" | sed 's/\.[^.]\+//') gcc "$F" -o "$X" "$@" ./"$X"

edited Mar 17, 2017 at 17:21

answered Mar 17, 2017 at 5:20

yugr

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2 Comments

Barmar Over a year ago

Put $@ in double quotes

yugr Over a year ago

@Barmar Done. I didn't bother in the first place, given that original code had much more serious problems.

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